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Home » = 12h \quad \Rightarrow \quad h = \frac28812 = 24 \text センチメートル - Network4

= 12h \quad \Rightarrow \quad h = \frac28812 = 24 \text センチメートル - Network4

📅 May 19, 2026 👤 scraface

May 19, 2026

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Given: \( x^2 - y^2 = 45 \) and \( x + y = 13 \).
Factor the first equation: \( (x-y)(x+y) = 45 \).
Substitute \( x+y = 13 \): \( (x-y)(13) = 45 \).
Thus, \( x-y = \frac{45}{13} \).
\( x + y = 13 \)
\( x - y = \frac{45}{13} \)
Add the equations: \( 2x = 13 + \frac{45}{13} = \frac{169 + 45}{13} =...
So, \( x = \frac{107}{13} \).
Substitute back to find \( y \): \( y = 13 - \frac{107}{13} = \frac{16...
The numbers are \( \frac{107}{13} \) and \( \frac{62}{13} \).

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ext{proj}_{\mathbf{c}} \mathbf{v} = rac{-3}{6} egin{pmatrix} 1 \ 2 \...
Now compute the perpendicular component:
\mathbf{v}_{\perp} = egin{pmatrix} 2 \ -1 \ 3 \end{pmatrix} - egin{p...
The magnitude of the perpendicular component (which is the desired qua...
\|\mathbf{v}_{\perp}\| = \sqrt{(2.5)^2 + 0^2 + (2.5)^2} = \sqrt{6.25 +...
Alternatively, using formula for perpendicular component magnitude:
\|\mathbf{v}_{\perp}\| = \sqrt{\|\mathbf{v}\|^2 - \left(rac{|\mathbf{...
But since we already computed it:
oxed{\dfrac{5\sqrt{2}}{2}}
A materials scientist is studying the symmetry of molecular arrangemen...

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