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At t=2, P=120; t=5, P=960.
So: 960 = 120e^(3r) → 8 = e^(3r) → ln(8) = 3r → r = ln(8)/3 = 3ln(2)/3 = ln(2) ≈ <<log(2)=0.6931>>0.6931.
But express multiplier per hour: e^r ≈ e^0.6931 ≈ <<exp(0.6931)=2>>2.

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