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Home » Akuma Street Fighter Throwdown: The Brutal Strategy Behind His Unmatched Power! - Network4

Akuma Street Fighter Throwdown: The Brutal Strategy Behind His Unmatched Power! - Network4

📅 May 19, 2026 👤 scraface

May 19, 2026

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📌 D: $a_n = 2^{n} \cdot 5 - 3 \cdot \frac{2^n - 1}{1}$

📌 Antwort: D $a_n = 2^{n} \cdot 5 - 3 \cdot \frac{2^n - 1}{1}$ — jedoch vereinfacht korrekt:

📌 Richtige Herleitung:

📌 Homogene Lösung: $a_n^{(h)} = A \cdot 2^n$

📌 Partikuläre Lösung: Konstant $C$, einsetzen: $C = 2C - 3 \Rightarrow C = 3$

📌 Allgemeine Lösung: $a_n = A \cdot 2^n + 3$

📌 Nutze $a_0 = 5$: $5 = A + 3 \Rightarrow A = 2$

📌 Also: $a_n = 2 \cdot 2^n + 3 = 2^{n+1} + 3$? Warte — Prüfe:

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