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alice in wonderland alice's adventures in wonderland - Network4

📅 May 20, 2026 👤 scraface

May 20, 2026

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u = rac{r^{1/2}}{\sqrt{c}}, \quad z = c \cdot rac{r^{1/2}}{\sqrt{c}}...
z^2 = c \cdot r \left(1 - rac{r^2}{c^2}
ight) = c r - rac{r^3}{c}
But \(r = rac{\sqrt{x^2 + y^2}}{1}\), so:
z^2 = c \sqrt{x^2 + y^2} - rac{(x^2 + y^2)^{3/2}}{c}
This is messy. Instead, return to the standard geometric interpretatio...
We know that the equation \(
ho = c \sin\phi\) in spherical coordinates represents a **sphere**.
Multiply both sides by \(
ho^2 = c

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