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Home » Ball KE = 0.5 × 2 × (15)² = 1 × 225 = 225 J - Network4

Ball KE = 0.5 × 2 × (15)² = 1 × 225 = 225 J - Network4

📅 May 19, 2026 👤 scraface

May 19, 2026

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Step 3: Combine using Chinese Remainder Theorem
We seek the smallest positive \( n \) such that:
\( n \equiv 1 \text{ or } 2 \pmod{3} \)
\( n \equiv 1 \text{ or } 4 \pmod{5} \)
\( n \equiv 1 \pmod{3}, n \equiv 1 \pmod{5} \Rightarrow n \equiv 1 \pm...
\( n \equiv 1 \pmod{3}, n \equiv 4 \pmod{5} \): Solve \( n = 5k + 4 \)...
\( n \equiv 2 \pmod{3}, n \equiv 1 \pmod{5} \): Let \( n = 5k + 1 \)....
\( n \equiv 2 \pmod{3}, n \equiv 4 \pmod{5} \): \( n = 5k + 4 \). Then...
So possible solutions: 1, 4, 11, 14. The smallest positive \( n > 1 \)...
4^2 = 16 \equiv 1 \pmod{15}? \quad 16 - 1 = 15 \equiv 0 \pmod{15} \Rig...

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