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BATES HOUSE OF TURKEY - Updated February 2026 - 122 Photos & 175 ...
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📰 Also: Für **alle** $ x \in \mathbb{Z} $ ist $ x \mid 0 $ wahr, und da $ x \mid y \Rightarrow y \mid x $ für alle $ x \in \mathbb{Z} $ gilt **vergleichsweise begrenzt**, nämlich für $ |x| \leq 1 $, und für $ |x| > 1 $ ist $ x \mid y \Rightarrow y \mid x $ falsz ⇒ $ P $ falsz ⇒ $ P \Rightarrow Q $ wahr. 📰 Aber ist $ x \mid y \Rightarrow y \mid x $ für **alle** $ x, y \in \mathbb{Z} $ wahr? 📰 Nein!** Gegenbeispiel: $ x = 2 $, $ y = 4 $: $ 2 \mid 4 $: wahr, $ 4 \mid 2 $? falsch ⇒ Implikation falsz.