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Home » Después de 2 años: \(10500 \times 1.05 = 11025\). - Network4

Después de 2 años: \(10500 \times 1.05 = 11025\). - Network4

📅 May 19, 2026 👤 scraface

May 19, 2026

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Mistake â try correct expansion:
Now add \(Ax + B\) (since divisor is quadratic, remainder is linear: \...
x^4 + (a - 1)x^3 + (b - a + 1)x^2 + (a - b + A)x + (b + B)
Match:
\(x^2\): \(b - a + 1 = -2 \Rightarrow b - 4 + 1 = -2 \Rightarrow b = 1...
\(x\): \(a - b + A = 1 \Rightarrow 4 - 1 + A = 1 \Rightarrow A = -2\)
constant: \(b + B = 5 \Rightarrow 1 + B = 5 \Rightarrow B = 4\)
So remainder is \(-2x + 4\)? But earlier substitution gave \(3\omega +...
Wait â recalculate at \(\omega\):
$\omega^2 = \omega - 1$

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