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Dont Ignore This: How to Change Your Microsoft Password Fast & Securely - Network4

📅 May 19, 2026 👤 scraface

May 19, 2026

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🔥 Popular Posts

Define \( f(u) = u - \frac{u^5}{5} \) for every real number \( u \). I...
We are given the recursive sequence defined by \( b_1 = 1 \) and \( b_...
Step 1: Analyze the function \( f(u) \)
Note that for \( u > 0 \),
f(u) = u - \frac{u^5}{5} < u,
so the sequence \( \{b_n\} \) is strictly decreasing as long as \( b_n...
Step 2: Compute initial terms numerically
We compute successive values:
\( b_2 = 1 - \frac{1^5}{5} = 1 - 0.2 = 0.8 \)
\( b_3 = 0.8 - \frac{(0.8)^5}{5} = 0.8 - \frac{0.32768}{5} = 0.8 - 0.0...

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Ya conocemos $x + y = 6$ y $x^2 + y^2 = 20$. Para usar la identidad, n...
Sustituyendo los valores conocidos:
6^2 = 20 + 2xy \implies 36 = 20 + 2xy \implies 2xy = 16 \implies xy =...
Ahora sustituimos de nuevo en la identidad de la suma de cubos:
x^3 + y^3 = (x + y)(x^2 - xy + y^2) = 6(20 - 8) = 6 \times 12 = 72
Por lo tanto, el valor de $x^3 + y^3$ es $\boxed{72}$.
Pregunta: Si $a + b = 10$ y $a^2 + b^2 = 58$, encuentra $a^3 + b^3$.
Usamos la identidad para la suma de cubos:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
Sabemos $a + b = 10$ y $a^2 + b^2 = 58$. Para encontrar $ab$, usamos:

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