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Home » Solution: Let $ x $ be the two-digit number. We are given: - Network4

Solution: Let $ x $ be the two-digit number. We are given: - Network4

📅 May 18, 2026 👤 scraface

May 18, 2026

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Letâs try factoring by grouping. Try factoring $ x^4 + 8x^2 + 16 $ a...
x^4 + 8x^2 + 16 = (x^2 + 4)^2
-16y^4 + 64 = -16(y^4 - 4) = -16(y^2 - 2)(y^2 + 2)
Letâs now expand and factor directly:
x^4 + 8x^2 + 16 - 16y^4 + 64 = x^4 + 8x^2 + 80 - 16y^4
Now factor $ x^4 + 8x^2 + 80 $:
Try factoring as $ (x^2 + a)^2 + b $, or test rational root theorem. L...
x^4 + 8x^2 + 80 = x^2(x^2 + 8) + 80
Not helpful. Try factoring as a quadratic in $ x^2 $:
Let $ u = x^2 $, then:

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