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Thick Asian Man Stuns the Internet with Stunning Confidence! - Network4

📅 May 18, 2026 👤 scraface

May 18, 2026

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📌 \frac{dV}{dt} = 4\pi (10)^2 (0.5) = 4\pi \times 100 \times 0.5 = 200\pi \text{ cm}^3/\text{s}

📌 The position of a particle moving along a line is given by \( s(t) = t^3 - 6t^2 + 9t + 2 \), where \( s \) is in meters and \( t \) in seconds. Find the time(s) when the particle is at rest.

📌 The particle is at rest when velocity \( v(t) = s'(t) = 0 \).

📌 v(t) = \frac{ds}{dt} = 3t^2 - 12t + 9

📌 Set \( v(t) = 0 \):

📌 3t^2 - 12t + 9 = 0

📌 t^2 - 4t + 3 = 0

📌 So, \( t = 1 \) or \( t = 3 \) seconds.

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