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A stable isotope analysis indicates a carbon isotope ratio of 0.011 in a bird's feathers. If the ratio increases by 0.002 every 10 days due to dietary changes, what will the ratio be after 50 days?
Determine the increase per 10 days:
Increase over 50 days = \( 0.002 \times \frac{50}{10} = 0.01 \).

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