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-3t^2 + 12 = 0 \Rightarrow t^2 = 4 \Rightarrow t = 2 \quad (\text{since } t \geq 0).
To confirm this is a maximum, note that $ C'(t) > 0 $ for $ 0 < t < 2 $ and $ C'(t) < 0 $ for $ t > 2 $, so the function increases then decreases. Thus, the maximum occurs at $ t = 2 $.
Question: A linguist is analyzing sentence structures and models the complexity of a sentence as $ f(n) = \frac{n^2 + 2n + 3}{n + 1} $, where $ n $ is the number of clauses. Find the minimum value of $ f(n) $ for $ n > 0 $.

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